What is the integral from 2 to infinity of-6x^{-2} ?

The integral from 2 to infinity of-6x^{-2} is -3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of-6x^{-2}

\int_{2}^{\infty} - 6 x^{- 2} d x

- 3

Solution steps

\int_{2}^{\infty} - 6 x^{- 2} d x

Compute the indefinite integral:

\int - 6 x^{- 2} d x = \frac{6}{x} + C

Compute the boundaries:

\int_{2}^{\infty} - 6 x^{- 2} d x = 0 - 3

= 0 - 3

Simplify

= - 3

\int \frac{1}{( x - 6 ) x ^{2} - 12 x} d x

\frac{d y}{d x} + (2 x y^{2}) = 0

\int_{1}^{8} x^{- \frac{5}{3}} d x

e^{x} (7 - 5 x + 3 x^{2}), at x = 0

\int 6 sec^{6} (x) d x

What is the integral from 2 to infinity of-6x^{-2} ?
The integral from 2 to infinity of-6x^{-2} is -3