What is the limit as x approaches 0 of ln((1+x)/x) ?

The limit as x approaches 0 of ln((1+x)/x) is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ln((1+x)/x)

x \to 0 lim (ln (\frac{1 + x}{x}))

Does not exist

Solution steps

x \to 0 lim (ln (\frac{1 + x}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (\frac{1 + x}{x})) = \infty

x \to 0 - lim (ln (\frac{1 + x}{x})) =

Does not exist

= Does not exist

\int (x^{2} cos (x)) d x

\int sin (\frac{n \cdot π}{3} x) d x

\int \frac{y}{1 + x y} d x

y = 1 - x^{2}, x = 2

\frac{x}{4 x + 8}

What is the limit as x approaches 0 of ln((1+x)/x) ?
The limit as x approaches 0 of ln((1+x)/x) is Does not exist