What is the derivative of-5sin(2x) ?

The derivative of-5sin(2x) is -10cos(2x)

What is the first derivative of-5sin(2x) ?

The first derivative of-5sin(2x) is -10cos(2x)

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\frac{d}{d x} (- 5 sin (2 x))

- 10 cos (2 x)

Solution steps

\frac{d}{d x} (- 5 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 5 cos (2 x) \cdot 2

Simplify

= - 10 cos (2 x)

\frac{d}{d x} (cos (x + 1))

x^{2} y^{^{''}} - 4 x y^{^{'}} - 36 y = 0

\frac{\partial}{\partial x} (x y cos (3 x) + e^{x y})

(x + 1) y^{^{'}} - y = x

\int (2 x^{5}) d x

What is the derivative of-5sin(2x) ?
The derivative of-5sin(2x) is -10cos(2x)
What is the first derivative of-5sin(2x) ?
The first derivative of-5sin(2x) is -10cos(2x)