What is the derivative of 3ax^2+2bx+c ?

The derivative of 3ax^2+2bx+c is 6ax+2b

What is the first derivative of 3ax^2+2bx+c ?

The first derivative of 3ax^2+2bx+c is 6ax+2b

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\frac{d}{d x} (3 a x^{2} + 2 b x + c)

6 a x + 2 b

Solution steps

\frac{d}{d x} (3 a x^{2} + 2 b x + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 a x^{2}) + \frac{d}{d x} (2 b x) + \frac{d c}{d x}

\frac{d}{d x} (3 a x^{2}) = 6 a x

\frac{d}{d x} (2 b x) = 2 b

\frac{d c}{d x} = 0

= 6 a x + 2 b + 0

Simplify

= 6 a x + 2 b

\int (4 x^{2} - 2) x d x

y = sin (sin (x)), (3 π, 0)

\frac{\partial}{\partial x} (sin (x^{2} - 5 x y))

\int \frac{1}{3 x} d x

\frac{d}{d x} ((e^{(x^{2})} + 4)^{2} (4 x)^{3} x)

What is the derivative of 3ax^2+2bx+c ?
The derivative of 3ax^2+2bx+c is 6ax+2b
What is the first derivative of 3ax^2+2bx+c ?
The first derivative of 3ax^2+2bx+c is 6ax+2b