What is the limit as x approaches 1 of log_{4}(x) ?

The limit as x approaches 1 of log_{4}(x) is 0

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limit as x approaches 1 of log_{4}(x)

x \to 1 lim (lo g_{4} (x))

0

Solution steps

x \to 1 lim (lo g_{4} (x))

Plug in the value

x = 1

= lo g_{4} (1)

Apply log rule:

lo g_{a} (1) = 0

= 0

x \to 8 + lim (\frac{1}{x - 8} - \frac{1}{x - 8})

x \to 4 lim (\frac{5 + x}{x - 4})

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\int t 7 t^{2} + 12 d t

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What is the limit as x approaches 1 of log_{4}(x) ?
The limit as x approaches 1 of log_{4}(x) is 0