What is laplacetransform 5*(t-8)-10*(t-4) ?

The answer to laplacetransform 5*(t-8)-10*(t-4) is -5/(s^2)

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laplacetransform 5(t-8)-10(t-4)

laplace transform

5 \cdot (t - 8) - 10 \cdot (t - 4)

- \frac{5}{s ^{2}}

Solution steps

L {5 (t - 8) - 10 (t - 4)}

Expand

5 (t - 8) - 10 (t - 4) : - 5 t

= L {- 5 t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {t}

L {t} : \frac{1}{s ^{2}}

= - 5 \cdot \frac{1}{s ^{2}}

Refine

- 5 \frac{1}{s ^{2}} : - \frac{5}{s ^{2}}

= - \frac{5}{s ^{2}}

\frac{\partial}{\partial x} (x^{3 x})

\int x (x^{3} - \frac{2}{x ^{2}} + 6) d x

x \to 0 lim (x^{2} - \frac{cos ( x )}{10000})

\frac{\partial}{\partial x} (ln (x + y^{3}) - z)

\int \frac{8 x ^{7}}{( x ^{8} + 1 ) ^{2}} d x

What is laplacetransform 5*(t-8)-10*(t-4) ?
The answer to laplacetransform 5*(t-8)-10*(t-4) is -5/(s^2)