What is the derivative of f(x)=x^2+10x+242x+8 ?

The derivative of f(x)=x^2+10x+242x+8 is 2x+252

What is the first derivative of f(x)=x^2+10x+242x+8 ?

The first derivative of f(x)=x^2+10x+242x+8 is 2x+252

Popular >

derivative of

f (x) = x^{2} + 10 x + 242 x + 8

2 x + 252

Solution steps

\frac{d}{d x} (x^{2} + 10 x + 242 x + 8)

Simplify

x^{2} + 10 x + 242 x + 8 : x^{2} + 252 x + 8

= \frac{d}{d x} (x^{2} + 252 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (252 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (252 x) = 252

\frac{d}{d x} (8) = 0

= 2 x + 252 + 0

Simplify

= 2 x + 252

\int 3 (e^{3 x} - e^{x}) d x

\int (\frac{1}{x ^{13}}) d x

\frac{d}{d x} (x^{2} sin^{8} (x) + x cos^{- 5} (x))

- 3 (x)^{5} + 9 (x)^{3}, at x = - 1

4 x^{2}, 16 x

What is the derivative of f(x)=x^2+10x+242x+8 ?
The derivative of f(x)=x^2+10x+242x+8 is 2x+252
What is the first derivative of f(x)=x^2+10x+242x+8 ?
The first derivative of f(x)=x^2+10x+242x+8 is 2x+252