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Popular >

y^'(x-1)+y(x-2)=0

Solution

y^{^{'}} (x - 1) + y (x - 2) = 0

Solution

y = e^{- \frac{x ^{2}}{2} + 2 x + c_{1}}

Solution steps

y^{'} (x) + y (x - 2) = 0

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + 2 x + c_{1}}

y = e^{- \frac{x ^{2}}{2} + 2 x + c_{1}}

Popular Examples

derivative of x^{0.5}*y^{0.5}

\frac{d}{d x} (x^{0.5} \cdot y^{0.5})

f (x) = e^{9 x}

(dx)/(dt)=(2500*7.75)/((1500-7.75t))

\frac{d x}{d t} = \frac{2500 \cdot 7.75}{( 1500 - 7.75 t )}

integral of e^{-st}

\int e^{- s t} d t

derivative of (Ax+Be^{-x})

\frac{d}{d x} ((A x + B) e^{- x})

Frequently Asked Questions (FAQ)

What is the solution for y^'(x-1)+y(x-2)=0 ?
The solution for y^'(x-1)+y(x-2)=0 is y=e^{-(x^2)/2+2x+c_{1}}