What is (\partial)/(\partial x)(5-3x^2-y^2) ?

The answer to (\partial)/(\partial x)(5-3x^2-y^2) is -6x

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(\partial)/(\partial x)(5-3x^2-y^2)

\frac{\partial}{\partial x} (5 - 3 x^{2} - y^{2})

- 6 x

Solution steps

\frac{\partial}{\partial x} (5 - 3 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (5) - \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (5) = 0

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 6 x - 0

Simplify

= - 6 x

\frac{d y}{d x} - x^{2} y = 0

\int x^{7} [0.7] d x

1 - x

\frac{d}{d x} (sec (x) \cdot tan (x))

tan (3 x^{2})

What is (\partial)/(\partial x)(5-3x^2-y^2) ?
The answer to (\partial)/(\partial x)(5-3x^2-y^2) is -6x