What is integral from 1 to 3 of f(x) ?

The answer to integral from 1 to 3 of f(x) is f*4

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integral from 1 to 3 of f(x)

\int_{1}^{3} f (x) d x

f \cdot 4

Solution steps

\int_{1}^{3} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{3}

= f [\frac{x ^{2}}{2}]_{1}^{3}

Compute the boundaries:

4

= f \cdot 4

\frac{d}{d x} (csc^{2} (2 x) - csc (2 x^{2}))

x \to 7 lim (\frac{x ^{2}}{x} - \frac{49}{7})

y = 4 x - 6 x^{3} + \frac{4}{x}

\frac{d y}{d x} + \frac{y}{x} = x

0.1 (0.7 n^{2} + 9 n + 29)^{(\frac{1}{2})}

What is integral from 1 to 3 of f(x) ?
The answer to integral from 1 to 3 of f(x) is f*4