What is (\partial)/(\partial y)(xy+1) ?

The answer to (\partial)/(\partial y)(xy+1) is x

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(\partial)/(\partial y)(xy+1)

\frac{\partial}{\partial y} (x y + 1)

x

Solution steps

\frac{\partial}{\partial y} (x y + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (1) = 0

= x + 0

Simplify

= x

\int \frac{1}{( x ^{3} - 8 ) ^{2}} d x

\int \frac{y ^{2} - 25}{y} d y

x \to 2 - lim (\frac{1}{x ^{3} - 2 x ^{2}})

\int x cos^{2} (2 x) d x

\frac{( - 1 )}{s ^{2} + 5 s + 6}

What is (\partial)/(\partial y)(xy+1) ?
The answer to (\partial)/(\partial y)(xy+1) is x