What is the limit as x approaches 0+of x^{5sin(x)} ?

The limit as x approaches 0+of x^{5sin(x)} is 1

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limit as x approaches 0+of x^{5sin(x)}

x \to 0 + lim (x^{5 s i n (x)})

1

Solution steps

x \to 0 + lim (x^{5 s i n (x)})

Apply exponent rules

= x \to 0 + lim (e^{5 s i n (x) l n (x)})

Apply the Limit Chain Rule:

1

= 1

\frac{\partial}{\partial z} (4 x ln (y) + y ln (z) - x)

(x - 4 y - 3) d x - (x - 6 y - 5) d y = 0

n \to \infty lim (cos (n))

x \to 0 lim (\frac{( sin ( 9 x ) )}{x})

f (x) = (x^{2} + 9 x + 2)^{5}

What is the limit as x approaches 0+of x^{5sin(x)} ?
The limit as x approaches 0+of x^{5sin(x)} is 1