What is the derivative of tsin(t) ?

The derivative of tsin(t) is sin(t)+tcos(t)

What is the first derivative of tsin(t) ?

The first derivative of tsin(t) is sin(t)+tcos(t)

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derivative of

t sin (t)

sin (t) + t cos (t)

Solution steps

\frac{d}{d t} (t sin (t))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = sin (t)

= \frac{d t}{d t} sin (t) + \frac{d}{d t} (sin (t)) t

\frac{d t}{d t} = 1

\frac{d}{d t} (sin (t)) = cos (t)

= 1 \cdot sin (t) + cos (t) t

Simplify

= sin (t) + t cos (t)

\frac{d}{d x} (\frac{x ^{4}}{4})

\int_{0}^{\frac{π}{20}} cos (5 x) d x

x \to 0 + lim (\frac{7}{x ^{3} + 2 x ^{2}})

\frac{d}{d x} (e^{2 x + l n (x)})

\frac{x ^{2} - x - 2}{x ^{2} + x - 6}

What is the derivative of tsin(t) ?
The derivative of tsin(t) is sin(t)+tcos(t)
What is the first derivative of tsin(t) ?
The first derivative of tsin(t) is sin(t)+tcos(t)