What is the derivative of 6cos(5x) ?

The derivative of 6cos(5x) is -30sin(5x)

What is the first derivative of 6cos(5x) ?

The first derivative of 6cos(5x) is -30sin(5x)

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\frac{d}{d x} (6 cos (5 x))

- 30 sin (5 x)

Solution steps

\frac{d}{d x} (6 cos (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (5 x))

Apply the chain rule:

- sin (5 x) \frac{d}{d x} (5 x)

= - sin (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 6 (- sin (5 x) \cdot 5)

Simplify

= - 30 sin (5 x)

\int \frac{9}{9 - x ^{2}} d x

\frac{\partial}{\partial x} (ln (\frac{x}{4} + \frac{y}{12}))

\int (e^{- x} sin (x)) d x

\int \frac{x ^{3} + 3 x ^{2}}{x ^{2} + 1} d x

(x^{2} + 1) \cdot \frac{d y}{d x} + 3 x y = 6 x

What is the derivative of 6cos(5x) ?
The derivative of 6cos(5x) is -30sin(5x)
What is the first derivative of 6cos(5x) ?
The first derivative of 6cos(5x) is -30sin(5x)