What is the solution for ((y^'-e^{-t}+5))/y =-5 ?

The solution for ((y^'-e^{-t}+5))/y =-5 is y= 1/(4e^t)-1+(c_{1})/(e^{5t)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y^'-e^{-t}+5))/y =-5

\frac{( y ^{^{'}} - e ^{- t} + 5 )}{y} = - 5

y = \frac{1}{4 e ^{t}} - 1 + \frac{c _{1}}{e ^{5 t}}

Solution steps

\frac{( y ^{'} ( t ) - e ^{- t} + 5 )}{y} = - 5

Solve linear ODE:

y = \frac{1}{4 e ^{t}} - 1 + \frac{c _{1}}{e ^{5 t}}

y = \frac{1}{4 e ^{t}} - 1 + \frac{c _{1}}{e ^{5 t}}

f (x) = 9 - x

\int 12 x^{5} y^{4} + 15 x^{4} y^{5}

ln (e + x^{2})

\int cos^{2} (x) x d x

(\frac{1}{x}), 2

What is the solution for ((y^'-e^{-t}+5))/y =-5 ?
The solution for ((y^'-e^{-t}+5))/y =-5 is y= 1/(4e^t)-1+(c_{1})/(e^{5t)}