What is the solution for (y+sqrt(x^2-y^2))dx-xdy=0 ?

The solution for (y+sqrt(x^2-y^2))dx-xdy=0 is y=sin(ln(x)+c_{1})x

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(y+sqrt(x^2-y^2))dx-xdy=0

(y + x^{2} - y^{2}) d x - x d y = 0

y = sin (ln (x) + c_{1}) x

Solution steps

(y + x^{2} - y^{2}) d x - x d y = 0

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

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f (x) = x^{3} - 6 x^{2} + 12 x - 9

\frac{\partial}{\partial y} (- 0.2 y + 23)

\frac{\partial}{\partial x} (- 5 x y (9 - x - y))

\int \frac{1}{( 16 x ^{4} + 8 x ^{2} + 1 )} d x

What is the solution for (y+sqrt(x^2-y^2))dx-xdy=0 ?
The solution for (y+sqrt(x^2-y^2))dx-xdy=0 is y=sin(ln(x)+c_{1})x