What is the solution for (dy)/(dx)=3(y^2+1),y(pi/4)=1 ?

The solution for (dy)/(dx)=3(y^2+1),y(pi/4)=1 is y=tan(3x-pi/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=3(y^2+1),y(pi/4)=1

\frac{d y}{d x} = 3 (y^{2} + 1), y (\frac{π}{4}) = 1

y = tan (3 x - \frac{π}{2})

Solution steps

\frac{d y}{d x} = 3 (y^{2} + 1)

Solve separable ODE:

y = tan (3 x - \frac{π}{2})

y = tan (3 x - \frac{π}{2})

y^{^{'}} - y = 2 t e^{2 t}

\frac{\partial}{\partial y} (2 x e^{x^{2} - y^{2}})

\int y e^{- y} d y

\frac{d}{d x} (cos^{2} (sin (4 x)))

y^{^{''}} + 5 y^{^{'}} + 6 y = 2 e^{x}, y (0) = 1, y^{^{'}} (0) = - 1

What is the solution for (dy)/(dx)=3(y^2+1),y(pi/4)=1 ?
The solution for (dy)/(dx)=3(y^2+1),y(pi/4)=1 is y=tan(3x-pi/2)