What is the derivative of sin(2x*2) ?

The derivative of sin(2x*2) is 4cos(2x)

What is the first derivative of sin(2x*2) ?

The first derivative of sin(2x*2) is 4cos(2x)

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\frac{d}{d x} (sin (2 x) \cdot 2)

4 cos (2 x)

Solution steps

\frac{d}{d x} (sin (2 x) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 cos (2 x) \cdot 2

Simplify

= 4 cos (2 x)

\frac{d}{d x} (a e^{v} + \frac{b}{v} + \frac{c}{v ^{2}})

\frac{\partial}{\partial u} (u^{9} + v^{7})

\int (cos (x))^{- 1} d x

\frac{d}{d x} (x^{\frac{1}{2}} (3 x^{2} - 35 x + 90))

What is the derivative of sin(2x*2) ?
The derivative of sin(2x*2) is 4cos(2x)
What is the first derivative of sin(2x*2) ?
The first derivative of sin(2x*2) is 4cos(2x)