What is the integral of (1/(1-x)) ?

The integral of (1/(1-x)) is -ln|1-x|+C

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integral of (1/(1-x))

\int (\frac{1}{1 - x}) d x

- ln ∣ 1 - x ∣ + C

Solution steps

\int \frac{1}{1 - x} d x

Apply u-substitution

: \int - \frac{1}{u} d u

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = 1 - x

= - ln ∣ 1 - x ∣

Add a constant to the solution

= - ln ∣ 1 - x ∣ + C

f (x) = 2 x^{2} + 2 x, (- 2, - 6)

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x^{^{''}} = - x + 3 x^{^{'}}

\int_{0}^{1} 2 π x (x) d x