What is the tangent of 3x^2+4x-2 ?

The tangent of 3x^2+4x-2 is y=(6a_{0}+4)x-3a_{0}^2-2

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tangent of 3x^2+4x-2

tangent of

3 x^{2} + 4 x - 2

y = (6 a_{0} + 4) x - 3 a_{0}^{2} - 2

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} + 4 a_{0} - 2)

Find the slope of

y = 3 x^{2} + 4 x - 2 : \frac{d y}{d x} = 6 x + 4

Compute the slope of

y = 3 x^{2} + 4 x - 2

x = a_{0} : m = 6 a_{0} + 4

Find the line with slope m=

6 a_{0} + 4

and passing through

(a_{0}, 3 a_{0}^{2} + 4 a_{0} - 2) : y = (6 a_{0} + 4) x - 3 a_{0}^{2} - 2

y = (6 a_{0} + 4) x - 3 a_{0}^{2} - 2

y = \frac{3}{x}, at x = \frac{1}{16}

(x^{2} + 1) y^{^{'}} = x y

\frac{d}{d x} (ln (tan (x) + sec (x)))

\int cos^{2} (2 u) d u

\int x^{3} - 6 x^{2} + 8 x d x

What is the tangent of 3x^2+4x-2 ?
The tangent of 3x^2+4x-2 is y=(6a_{0}+4)x-3a_{0}^2-2