What is the derivative of 3/(sqrt(x+9)) ?

The derivative of 3/(sqrt(x+9)) is -3/(2(x+9)^{3/2)}

What is the first derivative of 3/(sqrt(x+9)) ?

The first derivative of 3/(sqrt(x+9)) is -3/(2(x+9)^{3/2)}

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derivative of

\frac{3}{x + 9}

- \frac{3}{2 ( x + 9 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{x + 9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x + 9})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x + 9)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 9 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 9)

= - \frac{1}{2 ( x + 9 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 9)

\frac{d}{d x} (x + 9) = 1

= 3 (- \frac{1}{2 ( x + 9 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

3 (- \frac{1}{2 ( x + 9 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{3}{2 ( x + 9 ) ^{\frac{3}{2}}}

= - \frac{3}{2 ( x + 9 ) ^{\frac{3}{2}}}

y \cdot y^{^{'}} = \frac{5 x}{4 x ^{2} + 1}

\frac{x}{x ^{2} + 9}

\int \frac{1}{z ^{3} z ^{2} - 81} d z

\frac{\partial}{\partial x} (6 y^{8} x^{5} - 5 y^{7} x^{4})

What is the derivative of 3/(sqrt(x+9)) ?
The derivative of 3/(sqrt(x+9)) is -3/(2(x+9)^{3/2)}
What is the first derivative of 3/(sqrt(x+9)) ?
The first derivative of 3/(sqrt(x+9)) is -3/(2(x+9)^{3/2)}