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Popular >

y^'=((x-8))/x

Solution

y^{^{'}} = \frac{( x - 8 )}{x}

Solution

y = x - 8 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{( x - 8 )}{x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{x - 8}{x} d x

\int \frac{x - 8}{x} d x = x - 8 ln (x) + c_{1}

y = x - 8 ln (x) + c_{1}

Popular Examples

(\partial)/(\partial x)(U(x)(1+(R(x)^3)/(x^3)))

\frac{\partial}{\partial x} (U (x) (1 + \frac{R ( x ) ^{3}}{x ^{3}}))

area 2x+y^2=48,x=y area

2 x + y^{2} = 48, x = y

y^'+3y=4sin(e^{3x})

y^{^{'}} + 3 y = 4 sin (e^{3 x})

integral of (13)/(sqrt(25-9x^2))

\int \frac{13}{25 - 9 x ^{2}} d x

derivative of ((2x^2+3x))/(4x^2)derivative of

\frac{( 2 x ^{2} + 3 x )}{4 x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=((x-8))/x ?
The solution for y^'=((x-8))/x is y=x-8ln(x)+c_{1}