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Popular >

derivative of axsin(2x+bxcos(2x))

Solution

\frac{d}{d x} (a x sin (2 x) + b x cos (2 x))

Solution

a (sin (2 x) + 2 x cos (2 x)) + b (cos (2 x) - 2 x sin (2 x))

Solution steps

\frac{d}{d x} (a x sin (2 x) + b x cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x sin (2 x)) + \frac{d}{d x} (b x cos (2 x))

\frac{d}{d x} (a x sin (2 x)) = a (sin (2 x) + 2 x cos (2 x))

\frac{d}{d x} (b x cos (2 x)) = b (cos (2 x) - 2 x sin (2 x))

= a (sin (2 x) + 2 x cos (2 x)) + b (cos (2 x) - 2 x sin (2 x))

Popular Examples

(dx}{dt}=-\frac{50)/pi x^{-3/2}

\frac{d x}{d t} = - \frac{50}{π} x^{- \frac{3}{2}}

integral of (sin(x)-2e^x+3sqrt(x))

\int (sin (x) - 2 e^{x} + 3 x) d x

integral of y^2(1/(y^5)+(y^4)/2)

\int y^{2} (\frac{1}{y ^{5}} + \frac{y ^{4}}{2}) d y

derivative of 6xarcsin(x)derivative of

6 x arcsin (x)

derivative of (t+e^t)(9-sqrt(t))derivative of

(t + e^{t}) (9 - t)

Frequently Asked Questions (FAQ)

What is the derivative of axsin(2x+bxcos(2x)) ?
The derivative of axsin(2x+bxcos(2x)) is a(sin(2x)+2xcos(2x))+b(cos(2x)-2xsin(2x))
What is the first derivative of axsin(2x+bxcos(2x)) ?
The first derivative of axsin(2x+bxcos(2x)) is a(sin(2x)+2xcos(2x))+b(cos(2x)-2xsin(2x))