What is the derivative of sec^2(2x+5)*2 ?

The derivative of sec^2(2x+5)*2 is 8sec^2(2x+5)tan(2x+5)

What is the first derivative of sec^2(2x+5)*2 ?

The first derivative of sec^2(2x+5)*2 is 8sec^2(2x+5)tan(2x+5)

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derivative of

sec^{2} (2 x + 5) \cdot 2

8 sec^{2} (2 x + 5) tan (2 x + 5)

Solution steps

\frac{d}{d x} (sec^{2} (2 x + 5) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec^{2} (2 x + 5))

Apply the chain rule:

2 sec (2 x + 5) \frac{d}{d x} (sec (2 x + 5))

= 2 sec (2 x + 5) \frac{d}{d x} (sec (2 x + 5))

\frac{d}{d x} (sec (2 x + 5)) = sec (2 x + 5) tan (2 x + 5) \cdot 2

= 2 \cdot 2 sec (2 x + 5) sec (2 x + 5) tan (2 x + 5) \cdot 2

Simplify

2 \cdot 2 sec (2 x + 5) sec (2 x + 5) tan (2 x + 5) \cdot 2 : 8 sec^{2} (2 x + 5) tan (2 x + 5)

= 8 sec^{2} (2 x + 5) tan (2 x + 5)

n \to 2 lim (n^{2})

f (x) = (5 x - 5) (2 x^{3} - x^{2} + 1)

\frac{\partial}{\partial u} (u^{5} + v^{9})

\int_{1}^{e^{4}} \frac{ln ^{3} ( x ^{2} )}{x} d x

\frac{d}{d x} (x^{\frac{4}{3}} + 4 x^{\frac{1}{3}})

What is the derivative of sec^2(2x+5)*2 ?
The derivative of sec^2(2x+5)*2 is 8sec^2(2x+5)tan(2x+5)
What is the first derivative of sec^2(2x+5)*2 ?
The first derivative of sec^2(2x+5)*2 is 8sec^2(2x+5)tan(2x+5)