What is the tangent of f(x)=x^2-7x+7,\at x=6 ?

The tangent of f(x)=x^2-7x+7,\at x=6 is y=5x-29

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-7x+7,\at x=6

tangent of

f (x) = x^{2} - 7 x + 7, at x = 6

y = 5 x - 29

Solution steps

Find the tangent point:

(6, 1)

Find the slope of

f (x) = x^{2} - 7 x + 7 : \frac{df ( x )}{d x} = 2 x - 7

Compute the slope of

f (x) = x^{2} - 7 x + 7

x = 6 : m = 5

Find the line with slope m=

5

and passing through

(6, 1) : y = 5 x - 29

y = 5 x - 29

f (x) = (6 - 3 x) (6 + 3 x), at x = 3

\int_{- 0.5}^{0.5} 1.5 x^{2} d x

y = (3 x - 2)^{2} (5 x + 4)

\frac{- 1}{s ^{2} - 1}

\frac{d}{d x} (\frac{2}{x} + x)

What is the tangent of f(x)=x^2-7x+7,\at x=6 ?
The tangent of f(x)=x^2-7x+7,\at x=6 is y=5x-29