What is the integral from x to x^2 of e^{t^2} ?

The integral from x to x^2 of e^{t^2} is (sqrt(pi))/2 \erfi(x^2)-(sqrt(pi))/2 \erfi(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x to x^2 of e^{t^2}

\int_{x}^{x^{2}} e^{t^{2}} d t

\frac{π}{2} erfi (x^{2}) - \frac{π}{2} erfi (x)

Solution steps

\int_{x}^{x^{2}} e^{t^{2}} d t

Use the nonelementary integral:

\int e^{t^{2}} d t = \frac{π}{2} erfi (t)

= [\frac{π}{2} erfi (t)]_{x}^{x^{2}}

Compute the boundaries:

\frac{π}{2} erfi (x^{2}) - \frac{π}{2} erfi (x)

= \frac{π}{2} erfi (x^{2}) - \frac{π}{2} erfi (x)

y = \frac{5 ( 1 - sin ( x ) )}{2 cos ( x )}

tan^{4} (x^{3})

f (x) = x^{2}, x = 5

f (x) = \frac{sin ( x )}{1 + 2 cos ( x )}

y^{^{'}} = y - 2

What is the integral from x to x^2 of e^{t^2} ?
The integral from x to x^2 of e^{t^2} is (sqrt(pi))/2 \erfi(x^2)-(sqrt(pi))/2 \erfi(x)