What is the limit as x approaches 7 of (2x+1)/(x-7) ?

The limit as x approaches 7 of (2x+1)/(x-7) is diverges

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limit as x approaches 7 of (2x+1)/(x-7)

x \to 7 lim (\frac{2 x + 1}{x - 7})

diverges

Solution steps

x \to 7 lim (\frac{2 x + 1}{x - 7})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 7 + lim (\frac{2 x + 1}{x - 7}) = \infty

x \to 7 - lim (\frac{2 x + 1}{x - 7}) = - \infty

= diverges

\int 2 cos (5 x) d x

\frac{d y}{d x} = y (4 x^{2} + 1)

y = \frac{x}{3}

8 π^{7}

\frac{d}{d y} ((x + y)^{2})

What is the limit as x approaches 7 of (2x+1)/(x-7) ?
The limit as x approaches 7 of (2x+1)/(x-7) is diverges