What is the d/(dt)(3sin(3t)) ?

The d/(dt)(3sin(3t)) is 9cos(3t)

What is the first d/(dt)(3sin(3t)) ?

The first d/(dt)(3sin(3t)) is 9cos(3t)

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\frac{d}{d t} (3 sin (3 t))

9 cos (3 t)

Solution steps

\frac{d}{d t} (3 sin (3 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (sin (3 t))

Apply the chain rule:

cos (3 t) \frac{d}{d t} (3 t)

= cos (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= 3 cos (3 t) \cdot 3

Simplify

= 9 cos (3 t)

(\frac{2 y}{x} + 2 x) + (2 ln (x) - 3) y^{^{'}} = 0

\frac{\partial}{\partial x} (\frac{26 x ^{2}}{( x - y ) ^{2}})

1 + 4 x^{2} - 2 x^{3}

\frac{d}{d x} (sin (x - 1) (x^{3}))

x - 4