What is the integral from 0 to pi of (1-sin(x)) ?

The integral from 0 to pi of (1-sin(x)) is pi-2

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integral from 0 to pi of (1-sin(x))

\int_{0}^{π} (1 - sin (x)) d x

π - 2

Decimal Notation

1.14159 \dots

Solution steps

\int_{0}^{π} 1 - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 1 d x - \int_{0}^{π} sin (x) d x

\int_{0}^{π} 1 d x = π

\int_{0}^{π} sin (x) d x = 2

= π - 2

x \to 13 lim (x - 4)

4 x^{3} - 2 x + 5

\int (x^{4} - 6 x^{2} - 2 x + 4) d x

0^{^{'}}

\frac{d y}{d x} = \frac{2 x}{e ^{2 y}}

What is the integral from 0 to pi of (1-sin(x)) ?
The integral from 0 to pi of (1-sin(x)) is pi-2