What is (\partial)/(\partial x)(sin(x+y+z)) ?

The answer to (\partial)/(\partial x)(sin(x+y+z)) is cos(x+y+z)

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(\partial)/(\partial x)(sin(x+y+z))

\frac{\partial}{\partial x} (sin (x + y + z))

cos (x + y + z)

Solution steps

\frac{\partial}{\partial x} (sin (x + y + z))

Treat

y, z

as constants

Apply the chain rule:

cos (x + y + z) \frac{\partial}{\partial x} (x + y + z)

= cos (x + y + z) \frac{\partial}{\partial x} (x + y + z)

\frac{\partial}{\partial x} (x + y + z) = 1

= cos (x + y + z) \cdot 1

Simplify

= cos (x + y + z)

\int \frac{x + 16}{x ^{2} + 22 x + 125} d x

\int 9 cos^{2} (x t a) n^{3} x d x

\frac{\partial}{\partial x} (ln (x + 2 y + 3 z))

x \to + 0 + lim ((1 + x)^{\frac{2}{x}})

\frac{( 2 + x )}{1 - x}

What is (\partial)/(\partial x)(sin(x+y+z)) ?
The answer to (\partial)/(\partial x)(sin(x+y+z)) is cos(x+y+z)