What is the solution for y^{''}+9y=cos(5t) ?

The solution for y^{''}+9y=cos(5t) is y=c_{1}cos(3t)+c_{2}sin(3t)-1/16 cos(5t)

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y^{''}+9y=cos(5t)

y^{^{''}} + 9 y = cos (5 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{16} cos (5 t)

Solution steps

y^{''} (t) + 9 y = cos (5 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{16} cos (5 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{1}{16} cos (5 t)

y = 2 x^{2} + 3 x, (- 2, 2)

\int \frac{( sin ( 3 x ) - cos ( 2 x ) )}{4} d x

x \to - 3 lim (\frac{x ^{2} - 4}{x - 2})

x \cdot 2^{x}

e^{- 8 x}

What is the solution for y^{''}+9y=cos(5t) ?
The solution for y^{''}+9y=cos(5t) is y=c_{1}cos(3t)+c_{2}sin(3t)-1/16 cos(5t)