What is the integral from 0 to 4 of 2/(x^2) ?

The integral from 0 to 4 of 2/(x^2) is diverges

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integral from 0 to 4 of 2/(x^2)

\int_{0}^{4} \frac{2}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{4} \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{4}

= 2 [- \frac{1}{x}]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\int_{- 1}^{1} 2 x^{2} d x

\frac{d}{d x} (\frac{- 20}{( 2 + x ) ^{2}})

x^{2} - 11, 10 x

(x, y) \to (0, 0) lim (\frac{e ^{x y} - 1}{x y})

\frac{\partial}{\partial x} (x^{4} + 3 y^{3})

What is the integral from 0 to 4 of 2/(x^2) ?
The integral from 0 to 4 of 2/(x^2) is diverges