What is the derivative of (-16x^2+1^2) ?

The derivative of (-16x^2+1^2) is -64x(-16x^2+1)

What is the first derivative of (-16x^2+1^2) ?

The first derivative of (-16x^2+1^2) is -64x(-16x^2+1)

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\frac{d}{d x} ((- 16 x^{2} + 1)^{2})

- 64 x (- 16 x^{2} + 1)

Solution steps

\frac{d}{d x} ((- 16 x^{2} + 1)^{2})

Apply the chain rule:

2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

= 2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

\frac{d}{d x} (- 16 x^{2} + 1) = - 32 x

= 2 (- 16 x^{2} + 1) (- 32 x)

Simplify

= - 64 x (- 16 x^{2} + 1)

\int_{2}^{5} \frac{5}{x ^{2} - 1} d x

x \to 5 - lim (\frac{x ^{5}}{( x - 5 )})

\frac{2 x ^{2} + 8 x + 2}{x}

\int \frac{cos ( x ) - tan ( x )}{cos ^{2} ( x )} d x

4 x

What is the derivative of (-16x^2+1^2) ?
The derivative of (-16x^2+1^2) is -64x(-16x^2+1)
What is the first derivative of (-16x^2+1^2) ?
The first derivative of (-16x^2+1^2) is -64x(-16x^2+1)