What is the derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) ?

The derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) is (2x)/(3(x^2)^{2/3)}+1/(2sqrt(x))

What is the first derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) ?

The first derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) is (2x)/(3(x^2)^{2/3)}+1/(2sqrt(x))

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derivative of

\frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}} + \frac{1}{2 x}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}} + \frac{1}{2 x}

\int (csc (x) + tan (x))^{2} d x

x y^{^{'}} = y + 2 x^{2} y

\frac{d}{d x} ((1 + 5 x^{2}) (x - x^{2}))

x \to 0 lim (\frac{2}{x ^{2} ( x + 7 )})

\frac{d}{d x} (e^{x} \cdot sin (2 x))

What is the derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) ?
The derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) is (2x)/(3(x^2)^{2/3)}+1/(2sqrt(x))
What is the first derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) ?
The first derivative of f(x)=\sqrt[3]{x^2}+sqrt(x) is (2x)/(3(x^2)^{2/3)}+1/(2sqrt(x))