What is (\partial)/(\partial x)(3x^2y-1) ?

The answer to (\partial)/(\partial x)(3x^2y-1) is 6xy

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(\partial)/(\partial x)(3x^2y-1)

\frac{\partial}{\partial x} (3 x^{2} y - 1)

6 x y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (3 x^{2} y) = 6 y x

\frac{\partial}{\partial x} (1) = 0

= 6 y x - 0

Simplify

= 6 x y

\int \frac{6 x + 2}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{x + 3}{x + 2})

\frac{d}{d x} (\frac{4}{4 - 10 x})

\frac{d}{d x} (\frac{x ^{2} - 2}{x})

x^{2} + 2 x y - y^{2} + x = 5, (3, 7)

What is (\partial)/(\partial x)(3x^2y-1) ?
The answer to (\partial)/(\partial x)(3x^2y-1) is 6xy