What is the derivative of 2+sin(x) ?

The derivative of 2+sin(x) is cos(x)

What is the first derivative of 2+sin(x) ?

The first derivative of 2+sin(x) is cos(x)

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\frac{d}{d x} (2 + sin (x))

cos (x)

Solution steps

\frac{d}{d x} (2 + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (sin (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

x \to 5 + lim (\frac{x - 5}{x - 5})

x \to 0 lim (x ln (x))

x y^{^{'}} - y = 2 x^{2} - x - 2

\int (cos (x) + 1)^{2} - (sin (x) + 1)^{2} d x

- 2 (\frac{d y}{d x}) + 6 x^{2} = 0

What is the derivative of 2+sin(x) ?
The derivative of 2+sin(x) is cos(x)
What is the first derivative of 2+sin(x) ?
The first derivative of 2+sin(x) is cos(x)