What is the tangent of y=cos(x),\at x= pi/4 ?

The tangent of y=cos(x),\at x= pi/4 is y=-(sqrt(2))/2 x+1/(sqrt(2))+pi/(4sqrt(2))

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tangent of y=cos(x),\at x= pi/4

tangent of

y = cos (x), at x = \frac{π}{4}

y = - \frac{2}{2} x + \frac{1}{2} + \frac{π}{4 2}

Solution steps

Find the tangent point:

(\frac{π}{4}, \frac{2}{2})

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = \frac{π}{4} : m = - \frac{2}{2}

Find the line with slope m=

- \frac{2}{2}

and passing through

(\frac{π}{4}, \frac{2}{2}) : y = - \frac{2}{2} x + \frac{1}{2} + \frac{π}{4 2}

y = - \frac{2}{2} x + \frac{1}{2} + \frac{π}{4 2}

y^{^{''}} + y^{^{'}} - y = 0

\frac{\partial}{\partial x} (\frac{4 x - 4 y}{4 x + 4 y})

\int_{- 2}^{6} (4 x) - (x^{2} - 12) d x

(y^{2} + y \cdot x) d x - x^{2} d y = 0

\frac{\partial}{\partial x} (\frac{x ^{3} \cdot y}{x ^{2} + y ^{2}})

What is the tangent of y=cos(x),\at x= pi/4 ?
The tangent of y=cos(x),\at x= pi/4 is y=-(sqrt(2))/2 x+1/(sqrt(2))+pi/(4sqrt(2))