What is the solution for y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1 ?

The solution for y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1 is y=2e^{3t}-5e^{3t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 1

y = 2 e^{3 t} - 5 e^{3 t} t

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 2 e^{3 t} - 5 e^{3 t} t

y = 2 e^{3 t} - 5 e^{3 t} t

\frac{2}{5 x + 3}

\int \frac{csc ^{2} ( x )}{cot ^{3} ( x )} d x

ln (4 x^{5} + 1)

\int cos^{7} (x t a) n^{3} x d x

\int - \frac{1}{5 - x} d x

What is the solution for y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1 ?
The solution for y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1 is y=2e^{3t}-5e^{3t}t