What is the integral of 7sin(2t) ?

The integral of 7sin(2t) is -7/2 cos(2t)+C

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integral of 7sin(2t)

\int 7 sin (2 t) d t

- \frac{7}{2} cos (2 t) + C

Solution steps

\int 7 sin (2 t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int sin (2 t) d t

Apply u-substitution

: \int sin (u) \frac{1}{2} d u

= 7 \cdot \int sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 7 \cdot \frac{1}{2} (- cos (u))

Substitute back

u = 2 t

= 7 \cdot \frac{1}{2} (- cos (2 t))

Simplify

7 \cdot \frac{1}{2} (- cos (2 t)) : - \frac{7}{2} cos (2 t)

= - \frac{7}{2} cos (2 t)

Add a constant to the solution

= - \frac{7}{2} cos (2 t) + C

f (x) = x^{2} - 4 x, g (x) = 0, x = 0, x = 4

\frac{\partial}{\partial y} (2 y^{\frac{3}{2}})

\frac{y ^{^{'}} - e ^{- t} + 3}{y} = - 3, y (0) = 4

y^{^{''}} - 3 y^{^{'}} - 4 y = 2 sin (t)

\frac{d}{d x} (5 x cos (x))