What is the derivative of ln(x*ln(x)) ?

The derivative of ln(x*ln(x)) is (2ln(x))/x

What is the first derivative of ln(x*ln(x)) ?

The first derivative of ln(x*ln(x)) is (2ln(x))/x

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\frac{d}{d x} (ln (x) \cdot ln (x))

\frac{2 ln ( x )}{x}

Solution steps

\frac{d}{d x} (ln (x) ln (x))

Simplify

ln (x) ln (x) : ln^{2} (x)

= \frac{d}{d x} (ln^{2} (x))

Apply the chain rule:

2 ln (x) \frac{d}{d x} (ln (x))

= 2 ln (x) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

\int_{- 1}^{1} \frac{x}{x ^{2} + x - 6} d x

\int \frac{x ^{2}}{256 - x ^{2}} d x

(tan^{2} (x))^{^{'}}

x \to 5 lim (\frac{( 13 - 4 x ^{2} + 69 )}{x - 5})

y = - x + 4, y = x^{2} + 3 x

What is the derivative of ln(x*ln(x)) ?
The derivative of ln(x*ln(x)) is (2ln(x))/x
What is the first derivative of ln(x*ln(x)) ?
The first derivative of ln(x*ln(x)) is (2ln(x))/x