What is the integral of (sec^2(1/(x^5)))/(x^6) ?

The integral of (sec^2(1/(x^5)))/(x^6) is -1/5 tan(1/(x^5))+C

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integral of (sec^2(1/(x^5)))/(x^6)

\int \frac{sec ^{2} ( \frac{1}{x ^{5}} )}{x ^{6}} d x

- \frac{1}{5} tan (\frac{1}{x ^{5}}) + C

Solution steps

\int \frac{sec ^{2} ( \frac{1}{x ^{5}} )}{x ^{6}} d x

Apply u-substitution

: \int \frac{sec ^{2} ( \frac{1}{u} )}{5 u ^{2}} d u

= \int \frac{sec ^{2} ( \frac{1}{u} )}{5 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{sec ^{2} ( \frac{1}{u} )}{u ^{2}} d u

Apply u-substitution

: \int - sec^{2} (v) d v

= \frac{1}{5} \cdot \int - sec^{2} (v) d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} (- \int sec^{2} (v) d v)

Use the common integral:

\int sec^{2} (v) d v = tan (v)

= \frac{1}{5} (- tan (v))

Substitute back

= \frac{1}{5} (- tan (\frac{1}{x ^{5}}))

Simplify

= - \frac{1}{5} tan (\frac{1}{x ^{5}})

Add a constant to the solution

= - \frac{1}{5} tan (\frac{1}{x ^{5}}) + C

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a x + b

\int_{1}^{4} x^{2} - 3 x + 12 d x

(x - 5) e^{x}

\frac{d}{d x} (\frac{cos ( x )}{x ^{5}})

What is the integral of (sec^2(1/(x^5)))/(x^6) ?
The integral of (sec^2(1/(x^5)))/(x^6) is -1/5 tan(1/(x^5))+C