What is (d^2)/(dydx)(sin(x^2+y^2)) ?

The answer to (d^2)/(dydx)(sin(x^2+y^2)) is -4xysin(x^2+y^2)

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(d^2)/(dydx)(sin(x^2+y^2))

\frac{d ^{2}}{d y d x} (sin (x^{2} + y^{2}))

- 4 x y sin (x^{2} + y^{2})

Solution steps

\frac{d ^{2}}{d y d x} (sin (x^{2} + y^{2}))

\frac{d}{d y} (sin (x^{2} + y^{2})) = cos (x^{2} + y^{2}) \cdot 2 y

= \frac{d}{d x} (cos (x^{2} + y^{2}) \cdot 2 y)

\frac{d}{d x} (cos (x^{2} + y^{2}) \cdot 2 y) = - 4 x y sin (x^{2} + y^{2})

= - 4 x y sin (x^{2} + y^{2})

\int \frac{e ^{x} e ^{x} + 2}{e ^{x} + 6} d x

\frac{d}{d x} (ln (e^{5 x}))

\int sin^{5} (\frac{x}{7}) cos (\frac{x}{7}) d x

x \to 1 + lim (x^{\frac{2}{x - 1}})

\frac{d ^{2}}{d x ^{2}} (\frac{( x - 3 ) ( x ^{2} + 3 x + 9 )}{x ^{3}})

What is (d^2)/(dydx)(sin(x^2+y^2)) ?
The answer to (d^2)/(dydx)(sin(x^2+y^2)) is -4xysin(x^2+y^2)