What is the solution for 13xy^'-2y=-(x^2)/(y^{12)} ?

The solution for 13xy^'-2y=-(x^2)/(y^{12)} is y=\sqrt[13]{-ln(x)x^2+c_{1}x^2}

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13xy^'-2y=-(x^2)/(y^{12)}

13 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{12}}

Solution steps

13 x y^{'} (x) - 2 y = - \frac{x ^{2}}{y ^{12}}

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What is the solution for 13xy^'-2y=-(x^2)/(y^{12)} ?
The solution for 13xy^'-2y=-(x^2)/(y^{12)} is y=\sqrt[13]{-ln(x)x^2+c_{1}x^2}