What is (\partial)/(\partial y)(2-y-2x) ?

The answer to (\partial)/(\partial y)(2-y-2x) is -1

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(\partial)/(\partial y)(2-y-2x)

\frac{\partial}{\partial y} (2 - y - 2 x)

- 1

Solution steps

\frac{\partial}{\partial y} (2 - y - 2 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2) - \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (2 x)

\frac{\partial}{\partial y} (2) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (2 x) = 0

= 0 - 1 - 0

Simplify

= - 1

\frac{\partial}{\partial x} (x^{2} y sin (\frac{1}{x}))

x \to 0 lim (- x^{3})

f (x) = x^{2} + 6

\int \frac{1}{y - y ln ( y )} d y

4 - 3 x

What is (\partial)/(\partial y)(2-y-2x) ?
The answer to (\partial)/(\partial y)(2-y-2x) is -1