What is the derivative of 2+9sin(x^2) ?

The derivative of 2+9sin(x^2) is 18xcos(x^2)

What is the first derivative of 2+9sin(x^2) ?

The first derivative of 2+9sin(x^2) is 18xcos(x^2)

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derivative of

2 + 9 sin (x^{2})

18 x cos (x^{2})

Solution steps

\frac{d}{d x} (2 + 9 sin (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (9 sin (x^{2}))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (9 sin (x^{2})) = 18 x cos (x^{2})

= 0 + 18 x cos (x^{2})

Simplify

= 18 x cos (x^{2})

x^{^{''}} + 2 x^{^{'}} + x = 0

\int 3 - 2 x + x^{2} d x

⎩ ⎨ ⎧ (\frac{( s + 1 ) ^{3}}{4})^{2} ⎭ ⎬ ⎫

\frac{d}{d x} (\frac{88 x}{99 x - 88})

\frac{d}{d x} (c x^{3})

What is the derivative of 2+9sin(x^2) ?
The derivative of 2+9sin(x^2) is 18xcos(x^2)
What is the first derivative of 2+9sin(x^2) ?
The first derivative of 2+9sin(x^2) is 18xcos(x^2)