What is (\partial)/(\partial x)(2xy+y^2) ?

The answer to (\partial)/(\partial x)(2xy+y^2) is 2y

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(\partial)/(\partial x)(2xy+y^2)

\frac{\partial}{\partial x} (2 x y + y^{2})

2 y

Solution steps

\frac{\partial}{\partial x} (2 x y + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 y + 0

Simplify

= 2 y

(- 4.5) (1.1)

1 - sec (x)

\int 6 x + 4 d x

\int \frac{e ^{2 x}}{e ^{2 x} + 1} d x

\frac{d}{d x} (\frac{2 x ^{2} - 13 x + 20}{( x - 1 ) ^{2}})

What is (\partial)/(\partial x)(2xy+y^2) ?
The answer to (\partial)/(\partial x)(2xy+y^2) is 2y