What is the limit as x approaches 1 of (x^2+x)/(x-1) ?

The limit as x approaches 1 of (x^2+x)/(x-1) is diverges

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limit as x approaches 1 of (x^2+x)/(x-1)

x \to 1 lim (\frac{x ^{2} + x}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{x ^{2} + x}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{x ^{2} + x}{x - 1}) = \infty

x \to 1 - lim (\frac{x ^{2} + x}{x - 1}) = - \infty

= diverges

6 t \frac{d y}{d t} + y = t^{5}

\frac{d}{d x} (1 + cos^{2} (x))

\int (x - 2) e^{x} d x

y = 2 arcsin (3) x^{5}

y = 5 - 7 x^{2}, (3, - 58)

What is the limit as x approaches 1 of (x^2+x)/(x-1) ?
The limit as x approaches 1 of (x^2+x)/(x-1) is diverges