What is the limit as x approaches 1 of 4/(2x-2) ?

The limit as x approaches 1 of 4/(2x-2) is diverges

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limit as x approaches 1 of 4/(2x-2)

x \to 1 lim (\frac{4}{2 x - 2})

diverges

Solution steps

x \to 1 lim (\frac{4}{2 x - 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{4}{2 x - 2}) = \infty

x \to 1 - lim (\frac{4}{2 x - 2}) = - \infty

= diverges

\frac{\partial}{\partial x} (6 x^{2} y^{2} + 5 x + 8 y^{3})

\int \frac{6 x ^{3} - 5}{x} d x

x \to 1 lim (\frac{x ^{15} - 1}{x ^{5} - 1})

(\frac{1}{1 - cos ( x )})^{^{'}}

What is the limit as x approaches 1 of 4/(2x-2) ?
The limit as x approaches 1 of 4/(2x-2) is diverges