What is (\partial)/(\partial x)(sin(2yx)) ?

The answer to (\partial)/(\partial x)(sin(2yx)) is cos(2yx)*2y

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(\partial)/(\partial x)(sin(2yx))

\frac{\partial}{\partial x} (sin (2 y x))

cos (2 y x) \cdot 2 y

Solution steps

\frac{\partial}{\partial x} (sin (2 y x))

Treat

y

as a constant

Apply the chain rule:

cos (2 y x) \frac{\partial}{\partial x} (2 y x)

= cos (2 y x) \frac{\partial}{\partial x} (2 y x)

\frac{\partial}{\partial x} (2 y x) = 2 y

= cos (2 y x) \cdot 2 y

\frac{d y}{d x} = \frac{2 y}{5 y - 2 x}

\int 3 tan (3 x) d x

\int \frac{2 x ^{2} - 2 x - 1}{x ^{3} - x ^{2}} d x

x \to - 2 lim (\frac{3 x ^{2} + a x + a + 9}{x ^{2} + x - 2})

\frac{5 s e ^{- 2 s}}{2 s ^{2} + 50}

What is (\partial)/(\partial x)(sin(2yx)) ?
The answer to (\partial)/(\partial x)(sin(2yx)) is cos(2yx)*2y