What is the derivative of x^2e^{2x} ?

The derivative of x^2e^{2x} is 2xe^{2x}+e^{2x}*2x^2

What is the first derivative of x^2e^{2x} ?

The first derivative of x^2e^{2x} is 2xe^{2x}+e^{2x}*2x^2

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derivative of

x^{2} e^{2 x}

2 x e^{2 x} + e^{2 x} \cdot 2 x^{2}

Solution steps

\frac{d}{d x} (x^{2} e^{2 x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{2 x}

= \frac{d}{d x} (x^{2}) e^{2 x} + \frac{d}{d x} (e^{2 x}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= 2 x e^{2 x} + e^{2 x} \cdot 2 x^{2}

\int tan^{4} (x) d x

6 + \frac{2 t}{1 + t ^{3}} - e^{- 0.02 t}

\frac{d}{d s} (e^{- s})

\int 5 cos (\frac{x}{2}) d x

x^{2} 16 - x^{2}

What is the derivative of x^2e^{2x} ?
The derivative of x^2e^{2x} is 2xe^{2x}+e^{2x}*2x^2
What is the first derivative of x^2e^{2x} ?
The first derivative of x^2e^{2x} is 2xe^{2x}+e^{2x}*2x^2